A ball is gently dropped from a height of 2metre if its velocity increases uniformly at the rate of 10 metre per second. After what time will it strike the ground?
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Answered by
0
Answer:
10+2=12 is correct answer
Answered by
1
Answer:
here,
h=2m
u=10 ms-1
g=10 ms-2
using s=ut+1/2*at2
10*t+1/2*9.8* t2
10t+4.9t2
t2=14.9
t=√14.9
t=3.86
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