Question

A ball is gently dropped from a height of 45 m. Calculate the time taken by the ball to reach
the ground. (Take g = 10 m/s2

Answer 1

Answer:

H = 1/2 g t²

45 = 1/2×10×t²

t = 3sec.

Answer 2

Answer:

5m

Explanation:

g= a

h=s

starting speed (u)= 0

last speed (v)=10m/s

a = g = 10 m/s^2

so,v^2 - u^2 = 2as

so,(10)^2 -(0) ^2 = 2*10*h

100 - 0 = 20*h

20*h = 100

h = 100/20

h = 5 m