Question

A ball is gently dropped from a height of 50 m. If its

velocity increases uniformly at the rate of 10 m s-2

, with

what velocity will it strike the ground? After what time will

it strike the ground?
​

Answer 1

Answer:

Let us assume, the final velocity with which ball will strike the ground be ‘v’ and time it takes to strike the ground be ‘t’.

Given parameters

Initial Velocity of the ball (u) = 0

Distance or height of fall (s) = 20 m

Downward acceleration (a) = 10 m s-2

As we know

2as = v2 – u2

v2 = 2as + u2

v2 = (2 x 10 x 20 ) + 0

v2 = 400

Final velocity of ball (v) = 20 ms-1

t = (v – u)/a

Time taken by the ball to strike (t) = (20 – 0)/10

t = 20/10

t = 2 seconds

The final velocity with which ball will strike the ground is (v) = 20 ms-1

The time it takes to strike the ground (t) = 2 seconds

Answer 2

Step-by-step explanation:

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