A ball is gently dropped from height of 20 m. if its velocity increase uniformly at the rate of 10m s- 2 with what velocity will it strike the ground? after what time will it strike the ground ?
sristi21:
hii
nice u
nothing u
Answers
Answered by
2
Hope it helps...!!
____________
Given that,
Distance(s)= 20m
Initial velocity(u)= 0m/s
Acceleration= 10m/s^-2
Using the relation Distance time,
s=v^2- u^2=2a
s= v^2-0=2*10
20=v^2-0=20
v^2-0=20*20
v^2=400(underoot)
v=20 m/s
Time=v=u=at
20=0+10
20 upon 10=0+10(t)=
time= 2 secs
________________
#Be Brainly✌️
____________
Given that,
Distance(s)= 20m
Initial velocity(u)= 0m/s
Acceleration= 10m/s^-2
Using the relation Distance time,
s=v^2- u^2=2a
s= v^2-0=2*10
20=v^2-0=20
v^2-0=20*20
v^2=400(underoot)
v=20 m/s
Time=v=u=at
20=0+10
20 upon 10=0+10(t)=
time= 2 secs
________________
#Be Brainly✌️
but write now i m busy so i talk u later on okkk plse
byyy
hm khane ja rhe h okk
gd ni8
sry agr tm hurt hue toh sry
Answered by
5
Here Is Your Answer!!!
Attachments:
Similar questions