A ball is gently dropped from the height of 20 m if its velocity increases uniformly at the rate of 10 M per second square with what velocity will it strike the ground and after what time it will strike the ground
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2 second will be the answer
fariya3:
thanks
Answered by
1
H = 1/2gt²
20 =1/2 x 10 t²
T²=4
T = 2sec
V = u +. At
= 10 x 2
= 20m/sec
20 =1/2 x 10 t²
T²=4
T = 2sec
V = u +. At
= 10 x 2
= 20m/sec
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