Question

A ball is hit at 60 degree at the horizontal with the kinetic energy k when the ball is at the highest point its kinetic energy will be

Answer 1

Answer:K/4

Explanation: K.E.  K=1/2 mv²

At higest point of projectile Vy=0 and Vx= Vcos@ (only horizontal component act)

So, K=1/2 m(Vx)²

         =1/2 m (V cos60)²

         =(1/2 mV² ) 1/4

         =K/4