A ball is horizontally thrown from the top of staircase in such a way that it reach to the bottom of last step having height 20 cm and breadth 14 cm then find out initial velocity of body (staircase having six steps).
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Horizontal distance covered by ball =nb
Vertical distance covered by ball =nh
If the time taken to hit the edge of nth step is t, then
nb=ut
nh=12gt2
Eliminating t, we get,
nh=12g(nbu)2
n=2hu2gb2
Same as example
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