Question

A ball is in rest position dropped from a certain height its velocity becomes 19.6 M per second near the surface of the earth and has acceleration of 10 M per second square calculate the time taken by a ball to reach on the surface of the earth

Answer 1

given u = 0 m/s
v = 19.6 m/s
a = 10 m/s^2
to find t,
v = u + at
t = (v - u) a
t = (19.6 - 0) 10
t = 1.96 sec

Answer 2

Hii Vandana

Please Check Your Answer It is Right or Wrong

According To The Formula

V = U + at
[V = 19.6M/Sec
[U = 0M/Sec
[A = 10M/Sec²
[ t = ?]

Now put it into the Formula

V = U + At
19.6 = 0 + 10*t
19.6 = 10t
t = 19.6/10
t = 1.96 Sec Ans

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