Question

A ball is kicked at an angle 30° with the vertical. If the horizontal component of its
velocity is 20 ms 1, find the maximum height and horizontal range.
Answer fast please

Answer 1

Answer:

1) The ball is kicked with 30° with vertical. So, its angle with horizontal is 60°.

2) Calculate the speed of projection by using cosine angle. uh = u cosθ. So, u = 19.6 × 2 = 39.2 m/s

3) Calculate maximum height using H = u2sin2θ/2g. You will get 58.8 m.

4) Calculate maximum range using R = u2sin2θ/g. You will get 135.8 m.

Answer 2

Answer:

Explanation:    1) The ball is kicked with 30° with vertical. So, its angle with horizontal is 60°.

2) Calculate the speed of projection by using cosine angle. uh = u cosθ. So, u = 19.6 × 2 = 39.2 m/s

3) Calculate maximum height using H = u2sin2θ/2g. You will get 58.8 m.

4) Calculate maximum range using R = u2sin2θ/g. You will get 135.8 m.