A ball is kicked at an angle of 30 degree with the horizontal component of its velocity is 20 m/s^-1 .find the maximum height and horizontal range .take g=10 m/s^2
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Answered by
1
Answer:
H=5 and R=20 root 3
Explanation:
H=u2sin2theta/2g
=20×20×1×1÷2×10×2×2
=5
R=u2sin2theta /g
=20×20×root3÷10
=20root3
Answered by
0
Answer:
Answer:
H=5 and R=20 root 3
Explanation:
H=u2sin2theta/2g
=20×20×1×1÷2×10×2×2
=5
R=u2sin2theta /g
=20×20×root3÷10
=20root3
Explanation:
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