a ball is kicked at an angle of 30° with the horizontal if the horizontal component of its velocity is 20m/s find the maximum height and horizontal range
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Answer:
H max = 5m if we consider g= 10m/s2
Explanation:
- Hmax=u2sin2theeta/2g
- Hmax=20×20×0.25/20
- Hmax= 5m
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