Question

A ball is kicked at an angle of 35° with the ground.
a) What should be the initial velocity of the ball so that it hits a target that is 30 meters away at a height of
1.8 meters?
b) What is the time for the ball to reach the target?

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

here is ur answer

a)  

x = V0 cos(35°) t  

30 = V0 cos(35°) t  

t = 30 / V0 cos(35°)  

1.8 = -(1/2) 9.8 (30 / V0 cos(35°))2 + V0 sin(35°)(30 / V0cos(35°))  

V0 cos(35°) = 30 √ [ 9.8 / 2(30 tan(35°)-1.8) ]  

V0 = 18.3 m/s  

b)  

t = x / V0 cos(35°) = 2.0 s