Question

A ball is kicked straight up in the air. It leaves the ground at 20 m/s. What will the hang time of the ball be?​

Answer 1

Answer:

2s

Explanation:

Answer 2

Given: A ball leaves the ground at 20 m/s.

To find: The hang time of the ball

Solution:

• Hang time is the total time when the ball is up in the air.
• So, it is calculated as the time taken to go up and come down, or twice the time taken to come down.

        $H_{t} = 2 * t$

• Here, $H_{t}$ is the hang time and t is the time taken for the ball to come down.

• Time taken is given by,

        $t = \frac{v}{a}$

• Here, v is the velocity of the ball and a is the acceleration.
• In this case, a is the acceleration due to gravity, g, whose value is 10 ms⁻².

        $t = \frac{20 ms^{-1} }{10ms^{-2} }$

           $= 2 s$

        $H_{t} = 2 * 2s$

              $= 4 s$

Therefore, the hang time of the ball is 4 s.