Question

A ball is kicked vertically upwardly from the ground with a velocity of 60m/s and reaches a maximum height(h),it then falls freely back to the ground and bounces upwards to a height of 5m.What is the maximum height?

Answer 1

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

$height=180\:meters$

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

the maximum height

$\boxed {\underline {\mathbb {GIVEN:-}}}$

• u(initial velocity)=60m/s
• v(final velocity)=0m/s
• g(acceleration due to gravity)=10m/s

$\boxed {\underline {\mathbb {FORMULA\:USED:-}}}$

$v^{2}=u^{2}+2gh$

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

Ball is vertically kicked upward $(u) =60m/s$

As we know that ball get stopped for some milliseconds in air i.e. $(v) =0m/s$

By using formula $v^{2}=u^{2}+2gh$

[← putted values in equation]

$20h=3600\\h=\frac{3600}{20}\\h=180m$

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[ most important thing:- when the ball is kicked for the first time than it could gain the highest possible height(h) it could achieve , but when the  ball falls back than some of it’s momentum/ energy get reduced and can’t achieve the height that ball had achieves for the first time. Hence we will find h for the first time only. ]

Answer 2

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