Math, asked by pananah, 1 month ago

A ball is launched from 8 feet off the ground at an initial vertical speed of 64 feet per second. It is aimed across a field at a target also 8 feet off the ground. The height of the ball at time, t, in seconds, is given by the function, h = –16t 2 + 64t + 8. It will take the ball __ seconds to hit its target.

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Answered by akmahatooffical
0

Step-by-step explanation:

A ball is launched from 8 feet off the ground at an initial vertical speed of 64 feet per second. It is aimed across a field at a target also 8 feet off the ground. The height of the ball at time, t, in seconds, is given by the function, h = –16t 2 + 64t + 8. It will take the ball a0 seconds to hit its target

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