Question

A ball is launched up so that it reaches a velocity of 35.0 m/s at a height of 50.0 meters. Determine a) the ball’s initial velocity b) the maximum height reached by the ball

Answer 1

2gh = v^2-u^2

2×-9.8×50=35^2-u^2

-980=1225-u^2

-980+1225=u^2

245 = u^2

√245= u

15.65= u

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