A ball is mass 200g falls from a height of 5m . what is its kinetic energy , when it just reaches the ground
Answers
Answered by
5
Total energy is conserved
Initial total energy = mgh
= [200 g × 10^-3 kg/g] × 9.8 m/s^2 × 5 m
= 9.8 Joule
Kinetic energy when it reaches the ground should be 9.8 Joule
Initial total energy = mgh
= [200 g × 10^-3 kg/g] × 9.8 m/s^2 × 5 m
= 9.8 Joule
Kinetic energy when it reaches the ground should be 9.8 Joule
Answered by
1
Answer:
we can find the kinetic energy by multiplying all the given terms.
So, K.E.=mgh
m = 200g
we need to convert mass from grams to kilograms
So, m= 200/1000
m= 0.2
Now, K.E.= 0.2*9.8*5
= 1.96*5
= 9.80 J or 9.8 J
Therefore, the kinetic energy when it just reaches the ground will be 9.8 Joules
Similar questions