Physics, asked by Mehermalhotra4428, 7 months ago

a ball is moving up an inclined plane when its velocity changes from 15m/s to 7m/s in 3sec what is its acceleration

Answers

Answered by surekhapaturu88
0

Answer:

4m/s2

Explanation:

A=v-u/2

A=15-7/2

A=8/2

A=4m/s2

Answered by sonuvuce
0

The acceleration of the ball is 2.67 m/s²

Explanation:

Given that

Initial velocity of the ball u = 15 m/s

Final velocity of the ball v = 7 m/s

Time t = 3 sec

If the acceleration is a

Then using the first equation of motion

v=u+at

7=15+a\times 3

\implies a=\frac{7-15}{3}

\implies a=-\frac{8}{3}=-2.67 m/s²

Negative sign indicates that the acceleration is in the opposite direction of motion of the ball

Hope this answer is helpful.

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