Question

A ball is moving with momentum of 5 kgm/s strikes against a wall at an angle of 45 and is reflected by same angle. Calculate the impulse.

Answer 1

Answer:

Initial momentum = 5 kg m/s

perpendicular component = 5 cos 45 = 5/√2 kg m/s

parallel component = 5 sin 45 = 5/√2 kg m/s

After hitting the wall, it reflects at same angle.

So magnitude will the same = 5 kg m/s

parallel component = 5 sin 45 = 5/√2 kg m/s

perpendicular component = -5 cos 45 = -5/√2 kg m/s

(- sign comes due to change in direction)

So you can see that there is no change in parallel component.

Only perpendicular component changes.

So change = 5/√2 kg m/s - (-5/√2 kg m/s)

                 = 5/√2 kg m/s+5/√2 kg m/s

                 = 10/√2 kg m/s

                 =5√2 kg m/s

Explanation:

Answer 2

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