Question

A ball is projected at 45° and its horizpntal range in 10m. velocity of projection is
a)7√3m m/s
b)15m/s
c)9.6m/s
d)7√3m/s

What is the Answer and solution?​

Answer 1

Answer:

Explanation:

NOW WE ALL KNOW THAT THERE IS NO ACCELERATION ACTING IN THE HORIZONTAL DIRECTION.

NOW WE KNOW THAT RANGE IS EQUAL IS VELOCITY IN X DIRECTION*TOF.

NOW VELOCITY IN X IS UCOS45. CONSIDER T AS TOF.

NOW CALCULATE TOF. IT WILL BE = 2USIN45/g.

NOW WE KNOW TOF AND VELOCITY MULTIPLY THEM EQUATE TO 10[AS GIVEN] . CONSIDERING G AS 10 WE WILL GET THE ANSWER AS 10M/S

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