Question

A ball is projected at angle theta from horizontal with speed u the average velocity of ball during projectile between it

Answer 1

Answer:

ucosθ

Explanation:

average velocity = (total displacement)/(total time)

total displacement =Range of the projectile=u²sin(2θ)/g

total time=time of flight= 2usin(θ)/g

=> avg. velocity= u²sin2θ

2usinθ

= ucosθ

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