A ball is projected from a building of height 20 metres at a speed of 30 metre per second making an angle 30 with the horizontal. Then time after which the ball strikes the ground is
Answers
Answered by
24
Answer:
4 seconds
Explanation:
The time the ball takes to reach the ground is only dependant on the vertical component of the velocity.
You can find the vertical component by usinx, where u is the initial velocity(30m/s) and x is the angle of projection(30°),
vertical component= usinx
= 30 x sin30°
=15 m/s
let gravity= 10m/s^2
now to find time use:
S=ut+1/2 at^2
S=displacement
t= time
S=ut+1/2 at^2
-20= 15t+ 1/2×-10t^2
5t^2-15t-20=0
t^2-3t-20=0
t= 4secs
hope it helps
Answered by
8
Answer:
4sec
hopes it helps you
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