a ball is projected from a building of height 20m at a speed of 30 m/sec making an angle 30 degrees then time after which ball strikes the ground is...(take g=10m/s²)
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Given : u=20 m/s θ=30o g=10 m/s2
We get sinθ=sin30o=21
Maximum height reached H=2gu2sin2θ=2020×20×(21)2=5m
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