A ball is projected from a point with some velocity Vo not at an angle 30 degree with the horizontal as shown in the figure consider a target at point q . the ball will hit the target,then velocity Vo is (1)2root5 (2)7.5 (3)4 (4)2root10
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Given :
Let the point Q be the maximum height, then we have
⇒ H(max) = 1/2 m
θ = 30°
To find :
Initial velocity, i.e., v₀
Calculation:
- We know that maximum height of projectile can be calculated by formula :
H (max) = v₀² sin²θ / 2g
⇒ H (max) = v₀² sin²30 / 2g
⇒ 1/2 = v₀² (1/2)² / (2 × 10)
⇒ v₀² = 40
⇒ v₀ = √40
⇒ v₀ = 2√10 m/s
- So correct answer is option (4) 2√10 m/s
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