Question

A ball is projected from ground at an angle of 30° with the horizontal. At the highest point of its motion, direction of its acceleration is​

Answer 1

Answer:

At the top point, horizontal displacement is equal to half the range, vertical displacement is equal to the maximum height of the projectile and time taken is half the time of flight.

Horizontal displacement is:

x=

2

R

=

2

u

2

sin(2θ)/g

x=

2×10

20

2

sin(60

o

)

=10

3

m

Vertical displacement is:

y=H=

2g

u

2

sin

2

θ

y=

2×10

20

2

sin

2

(30

0

)

=5 m

Magnitude of total displacement is:

s=

x

2

+y

2

s=

(10

3

)

2

+5

2

s=5

13

m

Time taken is:

t=

2

T

t=

2

2usinθ/g

t=

10

20sin(30

o

)

=1 s

Average velocity is:

v=

t

s

v=5

13

m/s