A ball is projected from ground speed 30 M per second .what is the average velocity for 0 to 4 second
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surface), we can use some simple math and physics to solve this.
On Earth, it will accelerate downwards at a rate of 9.8m/s29.8m/s2. This means that after 0.4 seconds, its downward velocity will be 9.8m/s2∗0.4s=3.92m/s9.8m/s2∗0.4s=3.92m/s.
Since it is projected horizontally, assuming there is no air friction, its horizontal velocity will not change.
Now simply find the resultant of these two velocities: 3.922+32−−−−−−−−√≈4.94m/s3.922+32≈4.94m/s.
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A ball is projected horizontally with a velocity of magnitude of 5m/s. What is its position and velocity after 1/4s?
On Earth, it will accelerate downwards at a rate of 9.8m/s29.8m/s2. This means that after 0.4 seconds, its downward velocity will be 9.8m/s2∗0.4s=3.92m/s9.8m/s2∗0.4s=3.92m/s.
Since it is projected horizontally, assuming there is no air friction, its horizontal velocity will not change.
Now simply find the resultant of these two velocities: 3.922+32−−−−−−−−√≈4.94m/s3.922+32≈4.94m/s.
1.5k Views · View 5 Upvoters
RELATED QUESTIONS (MORE ANSWERS BELOW)
A ball is projected horizontally with a velocity of magnitude of 5m/s. What is its position and velocity after 1/4s?
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