Question

A ball is projected from ground with a speed of 20 m/s at an angle of 45° with horizontal. There is a
wall of 25 m height at a distance of 10 m from the projection point. The ball will hit the wall at a
height of
A) 5 m
B) 7.5 m C) 10 m D) 12.5 m​

Answer 1

Explanation:

y = xtantheta - gx^2/u^2cos^2theta

RHS =10 x1 - 10 x 100 x 2/2 x 400 x 1

= 10 - 2000/800

y = 10 - 2.5

y = 7.5m

Hence, ball will hit the ball at 7.5m.