Question

A ball is projected
from ground with a speed of 30 m/s , find theta so that ball passes through point A. (g = 10 ms–²)​

Answer 1

Answer:

Given,

u=20m/s

g=10m/s

2

From 2nd equation of motion,

along x-axis

S

x

=u

x

t+

2

1

g

x

t

2

10=ucos45

0

t+0

10=20×

2

1

t

t=

2

1

sec

along y-axis

S

y

=u

y

t+

2

1

g

y

t

2

S

y

=usin45

0

t+

2

1

g

y

t

2

S

y

=20×sin45

0

×

2

1

−

2

1

×10×

2

1

×

2

1

S

y

=10−2.5=7.5m

The correct option is B.

solution

Step-by-step explanation:

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