A ball is projected from the foot of an inclined plane of inclination 30 degree at an angle 60 degree with the horizontal with velocity 20 root 3 metre per second the time after which the ball will strike the plane is?
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Explanation:
By formula of time of flight on inclined plane i.e.
, T=2usin(alpha)/g cos(theta). ,.
Here alpha is 60-30=30° ,which is angle of projection from inclined plane , and theta is 30° which is angle of inclination...
Therefore T = 2×20√3×(sin30°)/10(cos30°), where g=10m/s^2.
After solving this we get T=4 sec ,
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