Question

a ball is projected from top of tower with a velocity of 5m/s at an angle of 53 to horizontal. what is its speed when it is at a height of 0.45 m from the point of projection ??

Answer 1

Answer:

4 m/s

Explanation:acc to law of conservation of energy

1/2mv^2=mgh+1/2mv^2

1/2m(5)^2=mg(0.45)+1/2mv^2

v^2=(5)^2-2g(0.45)

v^2=25-9

v=4m/s