A ball is projected horizontally from a height of hundred metre from the ground with a speed of 20 metre per second taking g is equal to 10 metre per second the time taken to reach the ground is
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Given,
S = 100m
u = 20 m/s
g = 10 m/s
v = ?
t = ?
So, v2 = u2 + 2as
v2 = 20*20 + 2*10*100
v2 = 400+ 2000
v2 = 2400
v = 48.98 m/s
Now, v = u+ at
48.98 = 10t
t = 48.98 / 10
t = 4.8 sec.
S = 100m
u = 20 m/s
g = 10 m/s
v = ?
t = ?
So, v2 = u2 + 2as
v2 = 20*20 + 2*10*100
v2 = 400+ 2000
v2 = 2400
v = 48.98 m/s
Now, v = u+ at
48.98 = 10t
t = 48.98 / 10
t = 4.8 sec.
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