Question

A ball is projected horizontally from the top of a tower with a velocity v0 .it will be moving at an angle of 60 degree with a horizontal after time

Answer 1

Given :-

A ball is projected horizontally with a Velocity of ${V}_{0}$.

Angle of Projection = Ø = 60°

To find :- Time taken by ball to move with angle of 60°.

Vx = V0 ----(1)

Vy = gt ------(2)

tanØ = Vy/Vx

tan60° = gt/V0

√3 = gt/V0

t = √3 V0/g

Answer.......