Question

A ball is projected horizontally with a speed 60 m/s from the top of the tall building the speed of the ball at t= 8s will be





hey mate plz answer !!!!

I need your help


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Answer 1

Hey MATE!!!

Since it is a horizontal projection therefore initially no vertical velocity is present.

Things we know in x direction :

Ux = 60 m/s

ax = 0

Sx = 30t + 1/2(0)(t^2)

Sx = 60(8) = 480 m

Things we know in y direction :

Uy = 0m/s

ay = g

Sy = (0)t + 1/2(10)(8^2)

Sy = 320 m

Now speed at t = 8 sec would be given by considering both speed at

t = 8 in y and x direction :

Speed in x everytime remains constant, i. e., 60m/s

Speed in y at t = 8 is given by

v = u +at ==> v = 0 + 10(8) = 80 m/s

Now we consider both velocities as vectors so the velocity at t = 8 is :

√(vx^2 + vy^2)

=> √(60^2 + 80^2 )

=> √(3600 + 6400)

=> √10000

= 100 m/s Answer

Hope it helps

#Hakuna Matata :))

Answer 2

here is your answer by attached figure☺️

answer is 480 m

✌️✌️ I hope it help u ✌️✌️