A ball is projected horizontally with a velocity of 3 ms-1 what is the velocity of the ball after 0.4 second ? given=10ms-2
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ux=3 m/s
uy=0 m/s
v=?
t=0.4 sec
Applying 1st equation of motion
vy=uy+gt
=0+9.8×0.4
=3.92 m/s
Now finding the resultant of the both components
________
vfinal= √u2x+u2y
_______
v f= √32+3.922
______
v f = √24.3664
velocity (final)≈4.936 m/s
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