Question

A ball is projected horizontally with velocity 10 m/s from the top of a building 19.6 m high. The time taken by the ball to hit the ground is (g = 9.8 m/s2)
O Es
O 15 s
O 2 s
o 3 s​

Answer 1

Here, h = 19.6 m

g = 9.8 m/s^2

Using the formula

$t = \sqrt{ \frac{2h}{g} }$

$t = \sqrt{ \frac{2 \times 19.6}{9.8} }$

$t = \sqrt{2 \times 2}$

$t = 2 \: seconds$