A ball is projected obliquely with a velocity 49 m/s strikes the ground at a distance of 245 m from the point of projection. it remained in the air for ??
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Answered by
181
let the angle of projection be A.
Range R = 245 m u = 49 m/s g = 9.8 m/s
R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.
Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.
Range R = 245 m u = 49 m/s g = 9.8 m/s
R = u^2 sin2A / g
so sin2A = R * g/u^2 = 1 => A =45 deg.
Time of flight = R/(u cosA) = 245 *√2 /49 = 5√2 = 7.07 seconds.
Answered by
12
answer is 5 or 5√2
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