a ball is projected upward from the top of the building with a velocity 30m/s making an angle 30 degree with the horizontal after how much time the ball strikes the ground if the building is 100m high.
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'we have equation of motion
y_final= y_initial +ut-(1/2)gt^2
(Taking g=10m/s^2)
-70=0+25t-5t^2
-14=5t-t^2
t^2–5t-14=0
Solving this gives t=7 s t=-2s. Since time is greater than 0, we discard negative solution .
So it will take 7 sec (approx, because we have used approximate value of g) to reach the ground.
y_final= y_initial +ut-(1/2)gt^2
(Taking g=10m/s^2)
-70=0+25t-5t^2
-14=5t-t^2
t^2–5t-14=0
Solving this gives t=7 s t=-2s. Since time is greater than 0, we discard negative solution .
So it will take 7 sec (approx, because we have used approximate value of g) to reach the ground.
simranpreerkaur:
Asr
and u
ok
Amritsar
+1
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