A ball is projected upward with a velocity 40 m/s from the top of a cliff of 100m high total time taken by the ball to reach the ground is
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AyanStypayhorson:
The ball will take 2secs to reach the ground
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Here height of cliff is =100m
The distance travelled by stone =100+X-X
V=40m/s
S=UT +1÷2AT^2
100=0×t+1÷2at^2.........(1)
V^2= u^2+2as
40 =2a100
2a=40÷100
a=0.4÷2
=0.2
100=2×0.2×t^2
100=0.4×t^2
t^2=100÷0.4
t=15.8
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