a ball is projected upwards from the foot of a tower. the ball crosses yhe top of the tower twice after an interval of 6 sec and the ball reaches the ground after 12 sec .calculate the height of the tower...
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Time taken by ball to go upwards and Then downwards (to the ground) is 12 seconds. Hence, the total time to come down from upwards will be : 12s = 6s + 6s.
Thus, now, the time taken to reach T and U, and then Again come to T, (passing T two times) is 6 seconds.
Hence, total time taken to go T upto from the ground = (12 - 6) / 2
= 6/2 = 3 Seconds.
Let the time taken to reach U from ground is : 0 = U - 6 × 10. If we substitute this value in case one above the value of U = 60 m/s,
Height (H) = 60 × 3 -1/2 × 10 × 3 × 3
Now, substituting these values in above case 2, the height = 135 m.
Your answer is - Height of the tower is 135 m.
Time taken by ball to go upwards and Then downwards (to the ground) is 12 seconds. Hence, the total time to come down from upwards will be : 12s = 6s + 6s.
Thus, now, the time taken to reach T and U, and then Again come to T, (passing T two times) is 6 seconds.
Hence, total time taken to go T upto from the ground = (12 - 6) / 2
= 6/2 = 3 Seconds.
Let the time taken to reach U from ground is : 0 = U - 6 × 10. If we substitute this value in case one above the value of U = 60 m/s,
Height (H) = 60 × 3 -1/2 × 10 × 3 × 3
Now, substituting these values in above case 2, the height = 135 m.
Your answer is - Height of the tower is 135 m.
Khushnumatahseen:
yeah correct
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