Question

A ball is projected upwards from the top of a tower with a velocity of 50m s

Answer 1

complete the question

Answer 2

Case 1:-

Let us consider initial velocity from where the body is projected and final velocity at maximum height.

$u=50ms^{-1}$

$v=0ms^{-1}$

$2as=v^2-u^2$

$2g(H)=-2500$         (where g=9.8 and H is the maximum height.)

$H=\frac{-2500}{19.6}$

H=126.2626 m

Hence the ball is projected 126.2626 meters upwards.