Question

A ball is projected upwards with velocity u relative to the ground from an open lift moving
upwards with velocity 10 m/s and upward acceleration of 2 m/s. The displacement of the ball
at the instant when ball again meets the lift is 24.0 m. Find u: (in m/sec) (g = 10 m/s)​

Answer 1

Answer:

Given:-

Initial velocity (u1) = 10m/s

Accleration = 2m/s^2

To find:-

Distance

By applying v^2 - u^2 = 2as

0 - 100 = 2×2×s

100 = 4s

S = 100/4

= 25m

Given:-

Distance = 24m

Accleration due to gravity = 10m/s

To find:-

Initial velocity

By applying v^2 - u^2 = 2as

0 - u^2 = 2×10×24

u^2 = 480

u = √480

= 21.9089m/s.

Answer 2

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