Question

A ball is projected vertically up with a speed of 25 metre per second find the maximum height and time to reach the maximum height and the speed at the maximum height??​

Answer 1

$\boxed {\underline {\mathbb {FINAL\:ANSWER:-}}}$

$height=180\:meters$

speed at the maximum height =$0m/s$

$\boxed {\underline {\mathbb {TO\:FIND:-}}}$

the maximum height

speed at the maximum height

$\boxed {\underline {\mathbb {GIVEN:-}}}$

• u(initial velocity)=25m/s
• v(final velocity)=0m/s
• g(acceleration due to gravity)=10m/s

$\boxed {\underline {\mathbb {FORMULA\:USED:-}}}$

$v^{2}=u^{2}+2gh$

$\boxed {\underline {\mathbb {SOLUTION:-}}}$

Ball is vertically kicked upward $(u) =25m/s$

As we know that ball get stopped for some milliseconds in air i.e. $(v) =0m/s$

By using formula $v^{2}=u^{2}+2gh$

$0=625+2*10*h$ [← putted values in equation]

$20h=625\\h=\frac{625}{20}\\h=31.25m$

hence speed at maximum height$=0m/s$ As we know that ball get stopped for some milliseconds in air i.e. $(v) =0m/s$  

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[ most important thing:- when the ball is kicked for the first time than it could gain the highest possible height(h) it could achieve , but when the  ball falls back than some of it’s momentum/ energy get reduced and can’t achieve the height that ball had achieves for the first time. Hence we will find h for the first time only. ]

Answer 2

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