Question

A ball is projected vertically up with a speed of 50 M per second. find the maximum height ,the time to reach the maximum height ,and the speed at maximum height take( g=10m/s2)

Answer 1

Initial speed= u=50m/s
g=10m/s2
At maximum height V=0 m/s

Maximum height:
V²-u²=2as
0²-50²=2*-10*s
s=50*50/20
s=125m
∴maximum height reahed =125m
b) time taken to reach maximum height
t=u/g
t=50/10=5 sec
∴Time taken to reach maximum height =5 sec

c) the speed at half the maximum height:
s=125/2=62.5m
v=?
u=50m/s
a=-10m/s²
From  v²-u²=2as
V=√u²+2as
V=√50²+2x(-10)x 62.5
v=√2500-1250
v=√1250=35 m/s