Question

A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height. (g=10 m/s² ) (Ans: 125m; 5s; zero)

Answer 1

H=U^2/2g

= (50×50)/10×2

= 25×5

= 125m

time at height H = u/g

=50/10

=5s

velocity at height H is 0m/s