Question

a ball is projected vertically up with a speed of 50m/s a) find the maximum height b) find the time to reach maximum height​

Answer 1

Answer:

a) 125 m

b) 5 sec

Explanation:

a) Initial velocity of ball (u) = 50 m/s

Acceleration of ball = -g

final velocity at the heights point (v) = 0

so applying the 3rd equation of motion we get

v2 = u2 - 2ghmax

0 = (50)2 - 2×10×hmax

soo hmax = 2500/20 = 125m

b) v = u-gt

0 = 50 - 10t

therefore t = 5 sec

Hope u will understand...

Answer 2

Explanation:

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