A ball is projected vertically upward from the ground with a velocity U. find an expression for the maximum height H upto which the ball may reach.
Answers
Answered by
9
V^2=u^2-2gH
At max height ,velocity=0
0=u^2-2gH
-u^2=-2gH
H=u^2/2g
HOPE..IT HELPS U
At max height ,velocity=0
0=u^2-2gH
-u^2=-2gH
H=u^2/2g
HOPE..IT HELPS U
FireUpdate:
the answer is not clear to me! can you please explain me better?
see..v^2=u^2+2as is a kinematics formula..just put the values in it
ooo isee
thank you!
and when it is thrown upward it will be retarding with -g
yes, got it thanks..
And S is displacement so s becomes H,here
u wlcm..
Answered by
14
If a body is thrown vertically upwards with initial velocity u to a height h then there will be retardation (a=-g). So we have equations of motion as:
v=u-gt ………(1)
h=ut - 1/2gt^2 …….(2)
v^2-u^2=-2gh…….(3)
At maximum height v=0 so
From (3) we get
-u^2=-2gh
h=u^2/2g
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