Question

A ball is projected vertically upward with a speed of 50 m/s. then the speed at half of the maximum height is ( g=10)

Answer 1

Answer:

solved

Explanation:

Max. height H = u²/2g = 2500/20 = 125 m

v² = u² - 2gh

v²/2g = u²/2g - 2gh/2g = H - h = H/2

v² = gH

v = √gH = √1250 = 25√2 m/s