Question

A ball is projected vertically upward with a speed of 50m/s.
Find (a) the maximum height
(b) the time to reach the maximum height
(c) the speed at half the maximum height
( take g = 10m/s square)​

Answer 1

Answer:

Given ,

u = 50 m/s

a = g = 10 m/s²

maximum height is given as

Hmax = u² / 2g

          = 50² / 20

          = 2500 / 20

          = 125 m

time taken to reach maximum height is given as ,

t = u/g

 = 50 / 10

 = 5 sec

Speed at Hmax/2 can be found in the following way ,

u = 50 m/s

S = 125/2

a = 10 m/s²

v² = u² + 2aS

    = 2500 + 1250

    = 3750

v = √3750

  = 25√6m/s

Hope it helps :)

Answer 2

Explanation:

• I think it is helpful to you