Question

a ball is projected vertically upward with a velocity 10m/s time taken by it to reach the maximum height g=10 m/s²​

Answer 1

Given that,

• Velocity of the ball = 10 m/s (u)
• Final velocity = 0 (zero) (v)
• Time taken for the ball to reach it's maximum height = ?
• Value of g = 10 m/s^2

By applying first equation of motion,

• v = u - gt
• 0 = 10 m/s - 10 m/s^2 × t
• 10 m/s^2 × t = 10 m/s
• t = 10 m/s / 10 m/s^2
• t = 1 sec.

Therefore, the time take for the ball to reach it's maximum height is 1 second.

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