a ball is projected vertically upward with an initial velocity of u goes to a maximum height h before coming to ground.what is the value of h
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Explanation: here u is initial velocity h is height attended now
As we know h = ut +1/2(at^2)
Its final velocity at highest point is 0
So u/g=t
H=u^2/2g ,hope it would help ,please follow me
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